Redemption's Dice roll algorithm

[ORI]

Do you know how it works and if its really completely random?

Heres why I ask, I know some players who claim the Redem[tion die roller chances in contested rolls will always be biased towards 50/50 odds regardless of how many dice are rolled and without knowing how the Algorithem work its hard to prove one way or the other.

[Javokis]

Redemption doesn't use dice rolling in the vanilla game. The code for discipline calculations is based on dot level. To hit is rolled as a solid random dexterity value + plus weapon and effect modifiers against defender's dexterity plus effect modifiers. Here's the equations:

To hit (Found in effect.ned notes):

• [hit if random(Adex + weaponAccuracy) + Axoffense > random(Ddex) + Dxdefense]

To Damage (Found in effect.ned notes):

• [dam is random(Astr + weaponDamage) + Apotence + Axdamage - random(Dsoak [+ Dstamina]) [-Dfortitude] - Dxsoak]

Cast Discipline (Found in Discipline.java):

Code: [Select]

public boolean Fizzled(int level)
{
// never fizzle a scroll cast
if((casterThing.GetActorFlags2() & THING_AF2_SCROLLCAST) != 0)
return(false);

if(Math.random() < ( (float)(5 - level) / 100.0f))
return(true);

return(false);
}

As you can see there is no PnP dice roller in vanilla Redemption.

[ORI]

Oh no, Javo,Im sorry I must have put the question incorrectly, I ment the thing that happen when you do '%' in the chatbox to roll dice..

Is it just a basic  'round(Math.random() * 10)' ? 

(or however the syntax actually goes)

[Javokis]

There's no source code for that so I couldn't say beyond what it does when you use it.  Since that feature is C++ coded, I would think it's using one of the built in C++ algorithms for random. I can't say which one they're using.